8y^2+y=15

Solution for 8y^2+y=15 equation:

8y^2+y=15

We move all terms to the left:

8y^2+y-(15)=0

a = 8; b = 1; c = -15;
Δ = b2-4ac
Δ = 12-4·8·(-15)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{481}}{2*8}=\frac{-1-\sqrt{481}}{16}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{481}}{2*8}=\frac{-1+\sqrt{481}}{16}
$